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		<title>Latest posts for the topic "#036 - Jelly Beans (orange suits)"</title>
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				<title>#036 - Jelly Beans (orange suits)</title>
				<description><![CDATA[ Please use this thread for discussion about this card.]]></description>
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				<pubDate><![CDATA[Thu, 1 Mar 2007 18:58:25]]> GMT</pubDate>
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				<title>Re: #036 - Jelly Beans (orange suits)</title>
				<description><![CDATA[ probabilty...i should've stayed awake in Stat.....

help?]]></description>
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				<pubDate><![CDATA[Fri, 9 Mar 2007 04:55:41]]> GMT</pubDate>
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				<title>#036 - Jelly Beans (orange suits)</title>
				<description><![CDATA[ Hint:
<p><b>Spoiler:</b> (highlight to read)</p>
		<div id="spoiler">
			<p>How many jelly beans can you possibly pick out while still not even having 3 of each colour?</p>
		</div>]]></description>
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				<pubDate><![CDATA[Fri, 9 Mar 2007 10:26:09]]> GMT</pubDate>
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				<title>#036 - Jelly Beans (orange suits)</title>
				<description><![CDATA[ of course, you need to make an assumption that different colour equates to different flavour for the jelly beans.]]></description>
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				<pubDate><![CDATA[Sun, 11 Mar 2007 11:24:15]]> GMT</pubDate>
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				<title>#036 - Jelly Beans (orange suits)</title>
				<description><![CDATA[ This question was a lot harder before i reread the question. I thought they wanted 3 of a specific color.]]></description>
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				<pubDate><![CDATA[Tue, 13 Mar 2007 01:30:16]]> GMT</pubDate>
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				<title>Re: #036 - Jelly Beans (orange suits)</title>
				<description><![CDATA[ This may help:

<p><b>Spoiler:</b> (highlight to read)</p>
		<div id="spoiler">
			<p>What is the MAXIMUM number of jelly beans that you can take out WITHOUT having three of a kind? Play out a scenario in your head...it'll work out.</p>
		</div> 8) ]]></description>
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				<pubDate><![CDATA[Tue, 13 Mar 2007 01:53:28]]> GMT</pubDate>
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				<title>#036 - Jelly Beans (orange suits)</title>
				<description><![CDATA[ Hmmm....I think I'm missing something.  

Let's take the scenario that the jar had eight different coloured beans in, ie eight  beans:  Then there would never be three beans of the same colour.

The only time this could occur is if there were 24 beans in the jar, three of each colour.  Then there is the possibility that  21 beans could be pulled out before the next three were of the same colour.......

Gawd...this is sending me mad.....

JDC]]></description>
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				<pubDate><![CDATA[Wed, 14 Mar 2007 01:51:07]]> GMT</pubDate>
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				<title>Re: #036 - Jelly Beans (orange suits)</title>
				<description><![CDATA[ If you were to do that you may end up with something like this:

<p><b>Spoiler:</b> (highlight to read)</p>
		<div id="spoiler">
			<p> 112233445566778812345 (each number representing a different colour...</p>
		</div>

....therefore more of each colour than necessary...you simply need ONE colour that has three colours...and it doesn't matter which colour!

Good Luck :wink: ]]></description>
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				<pubDate><![CDATA[Wed, 14 Mar 2007 02:28:48]]> GMT</pubDate>
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				<title>#036 - Jelly Beans (orange suits)</title>
				<description><![CDATA[ First of all, by "large jar of eight different flavoured jelly beans" they are implying hundreds or possibly thousands of beans are in the jar. We don't know how many but we do know there are 8 different colors (assuming each color corresponds to a unique flavor).

Second, they want the number of beans you need to take out "to be certain of getting three of the same colour". They don't need to be taken out in a row. The three beans can be taken out at different times. 

Once you get that straight use the previous hints given and I think you'll see what the answer is.]]></description>
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				<pubDate><![CDATA[Wed, 14 Mar 2007 02:28:59]]> GMT</pubDate>
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				<title>#036 - Jelly Beans (orange suits)</title>
				<description><![CDATA[ Rumour has it there is a magic eye puzzle on the bottom half of the card. ]]></description>
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				<pubDate><![CDATA[Wed, 14 Mar 2007 12:12:40]]> GMT</pubDate>
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				<title>#036 - Jelly Beans (orange suits)</title>
				<description><![CDATA[ I've tried magic-eye-ing the bottom half - pretty much nothing. Some of the pattern matches up, some doesn't, and the part that does doesn't come up with anything.]]></description>
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				<pubDate><![CDATA[Wed, 14 Mar 2007 13:20:20]]> GMT</pubDate>
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				<title>#036 - Jelly Beans (orange suits)</title>
				<description><![CDATA[ And if none of the above works, try this...

<p><b>Spoiler:</b> (highlight to read)</p>
		<div id="spoiler">
			<p>If each number relates to a diferent colour, then the minimum number needed would be 3 - as in 111. However, as there are 8 colours, if we assume that we pull out beans in a specific order (eg 12345678) folowed by the same order again (12345678) we would only have two of each colour.</p>
		</div>

Therefore...
<p><b>Spoiler:</b> (highlight to read)</p>
		<div id="spoiler">
			<p>the next bean drawn will match one of the pairs making a three.</p>
		</div>]]></description>
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				<pubDate><![CDATA[Thu, 15 Mar 2007 12:39:11]]> GMT</pubDate>
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				<title>#036 - Jelly Beans (orange suits)</title>
				<description><![CDATA[ I don't see anything on the bottom half. What's it suppose to be?]]></description>
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				<pubDate><![CDATA[Thu, 15 Mar 2007 23:56:43]]> GMT</pubDate>
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				<title>#036 - Jelly Beans (orange suits)</title>
				<description><![CDATA[ Well....I thought I could see a "3" but then it turned into a cloud and then became a bunch of bubbles.

I don't think there's anything there apart from my overactive imagination :)

JDC]]></description>
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				<pubDate><![CDATA[Fri, 16 Mar 2007 00:02:58]]> GMT</pubDate>
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				<title>#036 - Jelly Beans (orange suits)</title>
				<description><![CDATA[ What I see in the bottom half:
<p><b>Spoiler:</b> (highlight to read)</p>
		<div id="spoiler">
			<p>If you use the cross your eyes method (er, just look at it and cross your eyes until you overlap two repeating pieces, like the vaguely heart-shaped ones) then something definitely pops out. It looked like a bag, like you get jelly beans in, to me, but it was hard to focus on, so maybe it's just a random thing.</p>
		</div> ]]></description>
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				<pubDate><![CDATA[Fri, 16 Mar 2007 00:21:44]]> GMT</pubDate>
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				<title>Re: #036 - Jelly Beans (orange suits)</title>
				<description><![CDATA[ Family effort on this one. My daughter asked her math teacher who was no help at all and i had a good think about it after looking at the hints above. we both come home on the same day with the same answer. What is the odds on that?]]></description>
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				<pubDate><![CDATA[Mon, 19 Mar 2007 01:12:57]]> GMT</pubDate>
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				<title>#036 - Jelly Beans (orange suits)</title>
				<description><![CDATA[ Congrats! Love it when the answer just hits you like a ton of bricks.]]></description>
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				<pubDate><![CDATA[Mon, 19 Mar 2007 21:56:21]]> GMT</pubDate>
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				<title>Re: #036 - Jelly Beans (orange suits)</title>
				<description><![CDATA[ erm.. i got this puzzle sorted but...

just about every part of this question is wrong.. and the answer also wrong if the question is right... Thers so many bits missing and so much left to assumption... but.. a least the way they do it is a little easier for people]]></description>
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				<pubDate><![CDATA[Sun, 1 Apr 2007 17:58:13]]> GMT</pubDate>
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				<title>Re: #036 - Jelly Beans (orange suits)</title>
				<description><![CDATA[ <p><cite>priathic wrote:</cite></p>
		<blockquote>erm.. i got this puzzle sorted but...

just about every part of this question is wrong.. and the answer also wrong if the question is right... Thers so many bits missing and so much left to assumption... but.. a least the way they do it is a little easier for people</blockquote>

What are you talking about?
This card is written just fine.
It's like the question where you have say 10 red socks and 15 blue socks in a drawer.  How many socks do you have to take out to be sure of a matching pair?]]></description>
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				<pubDate><![CDATA[Sun, 1 Apr 2007 18:34:19]]> GMT</pubDate>
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				<title>Re: #036 - Jelly Beans (orange suits)</title>
				<description><![CDATA[ Here's a bonus question for you probability geeks: How many jelly beans do you need to draw before you have greater than a 50% chance that you've got 3 of a kind? It's similar to the birthday paradox -- that you need just 23 people in a room before you have greater than even odds that two people have the same birthday. But doing it for 3 makes it a bit tougher.

Any thoughts?]]></description>
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				<pubDate><![CDATA[Mon, 2 Apr 2007 05:23:23]]> GMT</pubDate>
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				<title>Re: #036 - Jelly Beans (orange suits)</title>
				<description><![CDATA[ [edited to remove dupe post]]]></description>
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				<pubDate><![CDATA[Mon, 2 Apr 2007 05:45:27]]> GMT</pubDate>
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				<title>Re: #036 - Jelly Beans (orange suits)</title>
				<description><![CDATA[ I thought there was a magic eye too, but I'm not too good at them  :(

Does anyone think that the black beans are making pattern... because they seem to stick out a bit to me... again, maybe I'm looking for too much!]]></description>
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				<pubDate><![CDATA[Thu, 5 Apr 2007 15:46:33]]> GMT</pubDate>
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				<title>Re: #036 - Jelly Beans (orange suits)</title>
				<description><![CDATA[ there is definetly  a weird pattern, any colour has a string of the same following it, at the bottom eithr red or turqiouse looks like numbers, like 800 or something]]></description>
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				<pubDate><![CDATA[Sat, 14 Apr 2007 19:04:30]]> GMT</pubDate>
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				<title>Re: #036 - Jelly Beans (orange suits)</title>
				<description><![CDATA[ <p><b>Spoiler:</b> (highlight to read)</p>
		<div id="spoiler">
			<p>i did 8*8+1 wich got me 65 and was sure it was right but still came up incorrect??? help</p>
		</div>]]></description>
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				<pubDate><![CDATA[Wed, 25 Apr 2007 07:12:51]]> GMT</pubDate>
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				<title>Re: #036 - Jelly Beans (orange suits)</title>
				<description><![CDATA[ Method:

<p><b>Spoiler:</b> (highlight to read)</p>
		<div id="spoiler">
			<p>Just think how many you'd need to have been so unlucky as to just enough of every type of bean but not quite - your next go then MUST be your final bean because it will have to make at least one complete set.</p>
		</div>]]></description>
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				<pubDate><![CDATA[Wed, 25 Apr 2007 07:21:48]]> GMT</pubDate>
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				<title>Re: #036 - Jelly Beans (orange suits)</title>
				<description><![CDATA[ I wanted to say '3' in that I could just look into the jar and pull what I wanted :D ... but I know that it's not the correct answer.]]></description>
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				<pubDate><![CDATA[Fri, 27 Apr 2007 17:06:37]]> GMT</pubDate>
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				<title>#036 - Jelly Beans (orange suits)</title>
				<description><![CDATA[ martynpie explanation cleared it up for me.  I totally disagreed with the answer (I too was doing probability calculations) til I read his spoiler.  Thanks.]]></description>
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				<pubDate><![CDATA[Fri, 27 Apr 2007 18:27:06]]> GMT</pubDate>
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				<title>Re: #036 - Jelly Beans (orange suits)</title>
				<description><![CDATA[ <p><cite>priathic wrote:</cite></p>
		<blockquote>erm.. i got this puzzle sorted but...

just about every part of this question is wrong.. and the answer also wrong if the question is right... Thers so many bits missing and so much left to assumption... but.. a least the way they do it is a little easier for people</blockquote>

I thought this as well <b>BUT</b> once I got the answer right I could see that it made sense.

<p><b>Spoiler:</b> (highlight to read)</p>
		<div id="spoiler">
			<p>the Important thing to remember is that the question asks for ANY colour three times NOT a specific colour!</p>
		</div>]]></description>
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				<pubDate><![CDATA[Mon, 30 Apr 2007 12:52:31]]> GMT</pubDate>
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				<title>#036 - Jelly Beans (orange suits)</title>
				<description><![CDATA[ <p><cite>iamjrac wrote:</cite></p>
		<blockquote>martynpie explanation cleared it up for me.  I totally disagreed with the answer (I too was doing probability calculations) til I read his spoiler.  Thanks.</blockquote>

You're very welcome  :mrgreen:]]></description>
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				<pubDate><![CDATA[Tue, 1 May 2007 07:08:22]]> GMT</pubDate>
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				<title>#036 - Jelly Beans (orange suits)</title>
				<description><![CDATA[ im still confused.............]]></description>
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				<pubDate><![CDATA[Sun, 1 Jul 2007 19:15:53]]> GMT</pubDate>
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				<title>Re: #036 - Jelly Beans (orange suits)</title>
				<description><![CDATA[ <p><cite>JewWario wrote:</cite></p>
		<blockquote>I wanted to say '3' in that I could just look into the jar and pull what I wanted :D ... but I know that it's not the correct answer.</blockquote>
yeah, I actualy entered that as well. Just in case it was a trick question. (you know these mind candt types like to confuse us)]]></description>
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				<pubDate><![CDATA[Mon, 2 Jul 2007 19:06:03]]> GMT</pubDate>
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				<title>Re: #036 - Jelly Beans (orange suits)</title>
				<description><![CDATA[ <p><cite>adaml43420 wrote:</cite></p>
		<blockquote>
What are you talking about?
This card is written just fine.
It's like the question where you have say 10 red socks and 15 blue socks in a drawer.  How many socks do you have to take out to be sure of a matching pair?</blockquote>

three :)]]></description>
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				<pubDate><![CDATA[Sat, 11 Aug 2007 08:54:19]]> GMT</pubDate>
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				<title>Re: #036 - Jelly Beans (orange suits)</title>
				<description><![CDATA[ WINNER!!!]]></description>
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				<pubDate><![CDATA[Sat, 11 Aug 2007 12:55:34]]> GMT</pubDate>
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				<title>#036 - Jelly Beans (orange suits)</title>
				<description><![CDATA[ <p><cite>pawn wrote:</cite></p>
		<blockquote>im still confused.............</blockquote>

Try thinking this way...

<p><b>Spoiler:</b> (highlight to read)</p>
		<div id="spoiler">
			<p>How many beans would you have if you could look in the jar and pick out one of each colour? Now, if you were to close your eyes and pick at random from the jar, how many would you have to take out in order to have two beans in <i>any</i> colour?

Once you have that, expand it to include the criteria of <i>three</i> of any colour.</p>
		</div>

Hope it helps.]]></description>
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				<pubDate><![CDATA[Tue, 14 Aug 2007 12:37:39]]> GMT</pubDate>
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